[pstricks] doppellog.tex

[Herbert Voss]

Murty Kanury wrote:

> 10^(-n) becomes 10^(-[n-1]). The scale in the figure resulting from the 
> doppellog
> 
> example code implies that 10 times 10^(-n) = 10^(-[n+1]), which is 
> obviously
> 
> wrong.

yes, this is a bug, depends to the problem, that the labels
are set by TeX and the lines by PostScript code. This is
the reason for a lot of improvements. TeX has no "real"
floating point arithmetic. I need some time to do it in
the right way.

Herbert

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