[pstricks] PSTricks Digest, Vol 128, Issue 5
Buddy Ledger
buddyledger at gmail.com
Sun Sep 29 15:28:26 CEST 2013
Try pst-fit. The documentation shows an example of calculating 3rd data
point via 1st and 2nd column values using listplot.
-Buddy
On 29/09/2013 6:00 AM, pstricks-request at tug.org wrote:
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> Today's Topics:
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> 1. Requesting a new feature to create relative points based on
> two existing points (Counter Terrorist)
>
>
> ----------------------------------------------------------------------
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> Message: 1
> Date: Sat, 28 Sep 2013 03:51:08 -0700
> From: Counter Terrorist <the.counterterrorist at yahoo.com>
> To: PSTricks <pstricks at tug.org>
> Subject: [pstricks] Requesting a new feature to create relative points
> based on two existing points
> Message-ID:
> <1380365468.20053.YahooMailNeo at web162604.mail.bf1.yahoo.com>
> Content-Type: text/plain; charset="iso-8859-1"
>
> Dear folks,
>
> TikZ has an elegant way to define a new point that is relative to the 2 existing points.
> For example, $(1,2)!.75!(3,4)$, to define a new point that is three quarter on the way from (1,2) to (3,4).
>
> We have already ([]{B}A) syntax to define a new point on the line joining A and B. The current implementation
> only supports absolute Xnodesep, Ynodese, nodesep, offset, and angle. So far so good.
>
> If it is possible, I want to request a new key, namely, Relnodesep to define a new point ([Relnodesep=<value>]{B}A) such that its vector position is equal to ?<value> times vektor AB.?
> Of course?([Relnodesep=<value,offset=<...>,angle=<...>>]{B}A) must work as well.
>
> Thank you in advance.
>
>
> best regards,
>
> PGFTricks?
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