[pstricks] Re : pst-3d: viewpoint and viewangle

[mluque5130 at aol.com]

 Christian Hoffmann a écrit :

>this is more a mathematical question. 
 
>I want to draw 3D-pictures with a horizontal x-axis, a vertical z-axis and a diagonal y-axis. Assume ' viewport=1 2 3'. Which >value must have viewangle for a horizontal x-axis? Is there a formula or is my wish impossible? 

Hello,
 
It is necessary (I think) to modify the matrix of current transformation (CTM) defined by TVZ in pst-3d. Here are some examples with a documentation in French (sorry) to obtain a representation in cavalier perspective and projections on plans XOY, XOZ and YOZ.
Maybe you can adapt it to your example?

http://manuel.luque.perso.neuf.fr/pst-projection/

Best regards

Manuel

 


 

 



=
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://tug.org/pipermail/pstricks/attachments/20100627/d004f25a/attachment.html>