[pstricks] Points of Intersection
Christoph Bersch
usenet at bersch.net
Wed Mar 18 21:50:10 CET 2009
David Arnold wrote:
>
> Now, in pstricks I could do some trig, come up with some angles, and
> use a polar coordinate representation of the point C.
>
> What I am wondering is this: Is there a slicker way of accomplishing
> this goal of drawing a triangle with sides 4, 5, and 6 units?
Yes, you can use pst-eucl and construct the triangle like you would do
with geogebra:
\documentclass{article}
\usepackage{pst-eucl}
\begin{document}
\begin{pspicture}[showgrid=true](7,8)
\pstGeonode(0,4){A}(6,4){B}
\pstInterCC[RadiusA=\pstDistVal{4},
RadiusB=\pstDistVal{5}]{A}{}{B}{}{M}{N}
\pspolygon(A)(B)(M)
\end{pspicture}
\bigskip
\begin{pspicture}[showgrid=true](7,4)
\pnode(0,0){A}
\pnode(6,0){B}
\pstInterCC[PointSymbol=none,
PointName=none,
RadiusA=\pstDistVal{4},
RadiusB=\pstDistVal{5}]{A}{}{B}{}{M}{N}
\pspolygon(A)(B)(M)
\end{pspicture}
\end{document}
HTH,
Christoph
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