[pstricks] psgraph question

[Herbert Voss]

McGarry Vince wrote:
> On Dec 10, 2005, at 2:10 AM, Herbert Voss wrote:
> 
>> McGarry Vince wrote:
>>
>>> I may be confused, but I'm sure this used to work, placing the  
>>> origin  at the default (0,0), doesn't seem to work anymore unless  I  
>>> explicitly state the origin.
>>
>>
>> [ ... ]
>>
>>> This works now
>>
>>
>>> \begin{psgraph*}[Dx=1,Dy=40,arrows=->,arrowscale=2](0,0) (-6.5,-140) 
>>> (7.5,140){3in}{2in}
>>
>>
>> see page 101 of the documentation.
>>
> 
> Am I misreading the documentation? It says on page 102:
> 
> " if (xOrig,yOrig) is missing, it is substituted to (0, 0);"
> 
> which means, if I'm not mistaken, that  if (xOrig,yOrig) is missing,  
> then the value of (xOrig,yOrig) defaults to (0,0), which is the way  it 
> has been behaving.

oh, my fault. I forgot to change this part of the documentation.
The behaviour should be the same as for \psplot (hopefully)
and I suppose, that this was the reason why I changed it.

\psgraph(x,y)                -> \psgraph(0,0)(0,0)(x,y)
\psgraph(x0,y0)(x1,y1)       -> \psgraph(x0,y0)(x0,y0)(x1,y1)
\psgraph(x0,y0)(x1,y1)(x2,y2)


> BTW, Herbert, I want to thank you for all of the work to improve  

thanks :-)

> pstricks---I do use the newer macros, like psPolynomial, as you  
> suggersted in your followup email---this example is a mixture of old  
> code and new from revision of a book. There wasn't enough time for a  
> complete rewrite. The next revision, hopefully.

oh no problem. Thought, that you didn't know the package.

Herbert