[pstricks] Option shift of \pspicture

[Herbert Voss]

Etienne Riga wrote:
> It would seem that the option "shift" functions contrary to what
> is written in pstnews1-10: a positive value of "shift" lowers the
> pspicture.
> 
> In the following example
> \pspicture(-1.25pt,-1.92pt)(9.25pt,8.16pt)
> build to place a minipspicture in the text, I want the origin of
> the pspicture on the baseline of the text.
>     --- with the old syntax, that was easy: \pspicture[](,)(,)
>     --- today, one must add 1.92pt and 8.16pt, then  divide 1.92
> by 10.08 and write
>           \pspicture[shift=.1905](,)(,)
>           (theoretically -.1905 but practically today .1905)
> 
> It seems to to me that the value of the option "shift", rather
> than to relate
> to the height of pspicture, should take an absolute value.
> In the example above, one would write
>        \pspicture[shift=-1.92pt](,)(,)
> If the principle of the relative value is preserved, it is much
> easier
> to write
>        \lower1.92pt\hbox{\pspicture ... \endpspicture}

please try again with the
http://perce.de/LaTeX/pstricks/pstricks.tex  and

\listfiles
\documentclass[12pt]{article}

\usepackage{pstricks}
\begin{document}

foo\pspicture[shift=-1.92pt](-1.25pt,-1.92pt)(9.25pt,8.16pt)
\psframe(-1.25pt,-1.92pt)(9.25pt,8.16pt)
\endpspicture bar\pspicture(-1.25pt,-1.92pt)(9.25pt,8.16pt)
\psframe(-1.25pt,-1.92pt)(9.25pt,8.16pt)
\endpspicture baz\pspicture[shift=-8.16pt](-1.25pt,-1.92pt)(9.25pt,8.16pt)
\psframe(-1.25pt,-1.92pt)(9.25pt,8.16pt)
\endpspicture foo

\end{document}


Herbert