Germain BOYER germain.boyer at ac-toulouse.fr
Mon Sep 21 16:55:50 CEST 2009

Bonjour ,

Look a this tex file. There is questions in the tex file.
Thanks.

\documentclass[10pt]{article}

\usepackage[latin1]{inputenc}

\usepackage[T1]{fontenc}

\usepackage{calc}

% \usepackage[fleqn]{amsmath}

\usepackage{amsmath}

\usepackage{amsfonts,amssymb}

\usepackage{mathtools}

%----------------------------------------------------------------------------------------------------------------------------
\usepackage{geometry}
\geometry{a4paper,dvips}
\geometry{portrait}
\geometry{left=2cm,right=2cm,top=2cm,bottom=2cm}
%----------------------------------------------------------------------------------------------------------------------------

\usepackage[frenchb]{babel}
\frenchbsetup{StandardLists=true}

\begin{document}
%\abs{ \frac{4}{5} }
% the documentation of mathtools talks about \abs and \norm but it doesn't work
% \norm{ \dfrac{4}{5} \vect{AB} }
%
\noindent
10 \\
\begin{alignedat}{1} 10^1 &= 1 + 9 = 1 + 3\times 3=1+3k_1 \\ 10^2 &= 1 + 99 = 1 + 3\times 33=1+3k_2 \\ 10^3 &= 1 + 999 = 1 + 3\times 333=1+3k_3 \end{alignedat} \\
\\ \\
%\hspace*{-5pt}
%
%
% I write \hspace*{-5pt} because the following line was not in the left margin.
% Is it possible to do this for example by a setlength like \setlength{\tabcolsep}{0mm} or by other mean ?
%
%
\begin{alignedat}{3} 10^1 &= 1 + 9 & \quad 10^1 &= 1 + 9 & \quad & \text{line 01} \\ 10^2 &= 1 + 99 & \quad 10^2 &= 1 + 99 & \quad & \text{line 02} \\ 10^3 &= 1 + 999 & \quad 10^3 &= 1 + 999 & \quad & \text{line 03} \\ \end{alignedat} \\
%\hspace*{-5pt}
%
%
% I write \hspace*{-5pt} because the following line was not in the left margin.
% Sorry for my bad english. I hope you understand what i mean.
% Is it possible to do this for example by a setlength like \setlength{\tabcolsep}{0mm} or by other mean ?
%
%
\begin{alignedat}{1} 10^1 &= 1 + 9 = 1 + 3\times 3=1+3k_1 \\ 10^2 &= 1 + 99 = 1 + 3\times 33=1+3k_2 \\ 10^3 &= 1 + 999 = 1 + 3\times 333=1+3k_3 \end{alignedat} \\
%
%
% A solution is in the following lines but it's not a regular solution.
% For one block i can use flalign but the width of the block is \textwidth so parbox is better.
%
%
\parbox{\widthof{$10^3 = 1 + 999 = 1 + 3\times 333=1+3k_3$}}{\begin{align*}
10^1 &= 1 + 9 = 1 + 3\times 3=1+3k_1 \\
10^2 &= 1 + 99 = 1 + 3\times 33=1+3k_2 \\
10^3 &= 1 + 999 = 1 + 3\times 333=1+3k_3
\end{align*} } \\
%
%
% There is a space before the following line.
% Is it possible to control this space by a setlength like \setlength{\tabcolsep}{0mm} or by other mean ?
% It' possible to write \\[-1.5\baselineskip] after begin of flalign but it's not a regular solution.
%
%
\begin{flalign*}
10^1 &= 1 + 9 = 1 + 3\times 3=1+3k_1 & \\
10^2 &= 1 + 99 = 1 + 3\times 33=1+3k_2  \\
10^3 &= 1 + 999 = 1 + 3\times 333=1+3k_3
\end{flalign*}
%
%
% There is a space before the following line.
% Is it possible to control this space by a setlength like \setlength{\tabcolsep}{0mm} or by other mean ?
% It' possible to write \\[-1.5\baselineskip] after begin of flalign but it's not a regular solution
%
%
\begin{alignat*}{2}
x& = y_1-y_2+y_3-y_5+y_8-\dots
& = y'\circ y^*  && \text{by \eqref{eq:D}}\\
& = y(0) y'      && \text {by Axiom 1.}
\end{alignat*}
%
%
% of course two spaces : one for \end{alignat*} and one for \begin{align}
% Is it possible to control this
%
%
\begin{align*}
x& = y_1-y_2+y_3-y_5+y_8-\dots