[XeTeX] bug using \underbrace with unicode-math package

[Daniel Greenhoe]

Hi Phil,

On Tue, Sep 13, 2011 at 7:51 AM, Philip TAYLOR (Webmaster, Ret'd)
<P.Taylor at rhul.ac.uk> wrote:
> Or perhaps there is another way : ... replace the whole <prime><backslash><whatever> sequence :
> \XeTeXmathchardef \bracelu = 0 3 "23A7
> ...

Yes, that works great.
\XeTeXmathchardef\bracelu  = 0 3 "23A7
\XeTeXmathchardef\bracemu  = 0 3 "23A8
\XeTeXmathchardef\braceru  = 0 3 "23A9
\XeTeXmathchardef\bracebar = 0 3 "23AA
\XeTeXmathchardef\braceld  = 0 3 "23AB
\XeTeXmathchardef\bracemd  = 0 3 "23AC
\XeTeXmathchardef\bracerd  = 0 3 "23AD

Thank you very much for all your help. I really appreciate it.

Dan

On Tue, Sep 13, 2011 at 7:51 AM, Philip TAYLOR (Webmaster, Ret'd)
<P.Taylor at rhul.ac.uk> wrote:
> Is there no way you can copy-and-paste Unicode, Dan ?
> I can e-mail the correct source to you (zipped, if that
> might help), or place it on my web server, or whatever ...
> Trying to substitute those weird part-brace characters
> with \symbol {<whatever>} might be possible, but at
> the moment I cannot see how it might be done.
>
> Or perhaps there is another way : <prime><backslash><whatever>
> actually yields a number; you might try just using your
> hex constants (in a notation in which TeX understands them)
> to replace the whole <prime><backslash><whatever> sequence :
>
>
> \XeTeXmathchardef \bracelu = 0 3 "23A7
>
> \XeTeXmathchardef \bracemu = 0 3 "23A8
>
> \XeTeXmathchardef \braceru = 0 3 "23A9
>
> \XeTeXmathchardef \bracebar = 0 3 "23AA
>
> \XeTeXmathchardef \braceld = 0 3 "23AB
>
> \XeTeXmathchardef \bracemd = 0 3 "23AC
>
> \XeTeXmathchardef \bracerd = 0 3 "23AD
>
>
>
> ** Phil.
>