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<div class="moz-cite-prefix">Philip Taylor wrote:<br>
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cite="mid:172037ae-76dd-d00f-050b-31389324c178@Hellenic-Institute.Uk">
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Addressed in the code below. For a normal run, the user just says
"TeX <whatever>, and the output will be a non-zero decimal
such as 2.00001, 2.00002, etc. For the final run, the user says
"TeX \count 0 = 0 \input <whatever>", the code will then
round the counter up to the next exact integer, so the output will
be (e.g.,) "3.0". The only assumption is that not more than 65535
iterations will be required before a final run.<br>
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There was a spurious " sp" in the code as posted at "\seqno =
\seqtmp sp"; this should, of course, have read simply "\seqno =
\seqtmp", as \seqtmp contains a dimension, not an integer. A better
version is currently under development.<br>
-- <br>
<i>Philip Taylor</i><br>
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