Hello, As it was enough for me with the first of the possibilities that Oleg sent, I have adapted it a little bit \def\dboxit#1#2{$$\vcenter{\boxit{\hbox{$\displaystyle #1$}}}\eqdef{#2}$$}% and then use it as \dboxit{\sum_{i=1}^n a_i = {n(a_l+a_n)\over2}}{sumi} and it seems it works. Thank you again, Juan Mari