[pstricks] using postscript calc for length but not angle

[Jon Joseph]

Thanks Herbert. Works perfectly.


On Apr 18, 2011, at 5:00 AM, pstricks-request at tug.org wrote:

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>   1. using postscript calc for length but not angle (Jon Joseph)
>   2. Re: using postscript calc for length but not angle (Herbert Voss)
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> ----------------------------------------------------------------------
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> Message: 1
> Date: Sun, 17 Apr 2011 12:54:25 -0500
> From: Jon Joseph <josco.jon at gmail.com>
> To: pstricks at tug.org
> Subject: [pstricks] using postscript calc for length but not angle
> Message-ID: <F73C95A9-12FF-424B-939C-DFD1667FA38E at gmail.com>
> Content-Type: text/plain; charset=us-ascii
> 
> All:  I would like to set a pnode at \sqrt{3} and 30 degrees and let postscript make the square root calculation for me.  I'm looking for
> \pnode(1.732;30) but replace 1.732 with !3 sqrt.  How do I do this without pnode thinking I want the cartesian point \pnode(1.732, 30)?  Thanks, Jon.
> 
> 
> ------------------------------
> 
> Message: 2
> Date: Sun, 17 Apr 2011 20:47:19 +0200
> From: Herbert Voss <Herbert.Voss at FU-Berlin.DE>
> To: Graphics with PSTricks <pstricks at tug.org>
> Subject: Re: [pstricks] using postscript calc for length but not angle
> Message-ID: <4DAB35B7.5020500 at FU-Berlin.DE>
> Content-Type: text/plain; charset=ISO-8859-1; format=flowed
> 
> Am 17.04.2011 19:54, schrieb Jon Joseph:
>> All:  I would like to set a pnode at \sqrt{3} and 30 degrees and let postscript make the square root calculation for me.  I'm looking for
>> \pnode(1.732;30) but replace 1.732 with !3 sqrt.  How do I do this without pnode thinking I want the cartesian point \pnode(1.732, 30)?  Thanks, Jon.
> 
> \documentclass{minimal}
> \usepackage{pst-node} \SpecialCoor
> \begin{document}
> 
> \psset{unit=2}
> \begin{pspicture}(2,2)\psgrid
> \end{pspicture}
> 
> \pnode(! 3 sqrt 30 PtoC){A}\psdot(A)
> 
> \end{document}
> 
> Herbert
> 
> 
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