[pstricks] How to show a specific point of a function's curve?
Denis Bitouzé
dbitouze at wanadoo.fr
Mon Jan 24 10:04:17 CET 2011
Le lundi 24/01/11 à 09h19,
Herbert Voss a écrit :
> Am 23.01.2011 19:11, schrieb Denis Bitouz?:
>
> > What would be the best way to show the point of the curve (with a
> > qdisk on the point and two parallel
Of course, I meant parallel to the axes...
> > lines for its x- and y-values) just by specifying its x-value?
>
> \documentclass{article}
> \usepackage{pstricks-add}
> \psset{algebraic}
> \begin{document}
>
> \begin{psgraph}(0,0)(5,3){6cm}{!}
> \psplot{0}{5}{x^2/10}
> \qdisk(*3 {x^2/10}){2pt}% or \pnode(*3 {x^2/10}){Fx}
> \psline(3,0)(*3 {x^2/10})(0,0|*3 {x^2/10})
> \end{psgraph}
>
> \end{document}
>
> With the node definition it is
> \qdisk(Fx){2pt}
> \psline(3,0)(Fx)(0,0|Fx)
Thanks Herbert. Where is this feature documented?
Maybe it could be useful to automate this by a command such as:
\psshowpoint{x^2/10}{3}
with optional PointSymbol=... (as in pst-eucl).
--
Denis
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