[pstricks] {pst-eucl?} Drawing a circle with tangent

Hubert Lam pstricks at tug.org
Mon Aug 2 23:56:22 CEST 2010

Hi again all

No need to worry -- found the solution in the other example. Just draw
another circle! :0

\pstMiddleAB[PointSymbol=none, PointName=none]{O}{M}{O'}
\pstInterCC[RadiusA=\pstDistVal{2}, DiameterB=\pstDistAB{O}{M},
                                CodeFigB=true, CodeFigColor=magenta,
\psset{linecolor=red, linewidth=1.3\pslinewidth, nodesep=-2}



On Mon, 02 Aug 2010 08:35 +0200, "Herbert Voss"
<Herbert.Voss at fu-berlin.de> wrote:
> Am 02.08.2010 04:55, schrieb Hubert Lam:
> > In the documentation of pst-eucl the author shows how to draw a circle
> > with a tangent by specifying three points: the end points of the tangent
> > and the centre of the circle, then the point of contact is found by
> > \pstProjection (i.e. radius is perpendicular to point of contact) and
> > then the circle is drawn using \pstCircleOA.
> Hubert,
> to which page of the documentation do you refer?
> > Is there a way of using the macros in pst-eucl (and/or pstricks-add) to
> > specify the radius of the circle, and then drawing the tangent from
> > there without having to differentiate the semicircle function, find the
> > coordinates of the point of contact and then substitute into y = mx + b?
> Herbert
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