[pstricks] pst-3Dplot

Patrice Mégret Patrice.Megret at umons.ac.be
Thu Oct 1 14:50:07 CEST 2009

```Dear Herbert,

The way you try to implement the spherical coordinate system used by "electrical people" has two drawbacks:

1. The angle theta is now measured from the z-axis but also important is that the order of the coordinates should be (r,theta,phi) and not (r,phi',theta') as used in the original pst-3dplot. So here, with coorType=5, we have to keep the order (r,phi,theta).

2.In the previous pst-3dplot, coorType 0,1,2 and 3 are the way the axes x-y-z are projected into the plane. This means that it was possible to use the SphericalCoor with any one of these projection systems.   ==> the coordinate of the points are represented in Cartesian, cylindrical or spherical systems independently of the projection system represented by coorType.

So I believe that the modification should be done at the level of spherical to x,y,z (so 3D -> 3D) and then use the classical code you developed to go from 3D to any 2D systems. Maybe by introducing a key SphericalCoor2 but without changing the coorType?

Best regards,

Patrice

-----Message d'origine-----
De : pstricks-bounces at tug.org [mailto:pstricks-bounces at tug.org] De la part de Herbert Voss
Envoyé : jeudi 24 septembre 2009 23:13
À : Graphics with PSTricks
Objet : Re: [pstricks] pst-3Dplot

Patrice Mégret schrieb:

> In the attached files you will find the transformation from the proposed spherical coordinates to (x,y,z). Then from (x,y,z) to (x2d,y2d) it is your subroutines depending on CoorType key.
>
> In fact the spherical coordinate system used in electromagnetism (r,theta_2,phi_2) is nearly the same as the one you used (r,phi_1,theta_1) except that (1) latitude is measured from the z-axis and from not the xy plane, and (2) the order is r, theta_2, phi_2 and not r, phi_1, theta_1.
>
> This change also implies theta_2=pi/2 -theta_1.

Patrice,
try
it with the pst-3dplot.pro from here
http://voss.homedns.org/packages/pst-3dplot/

you have to set \psset{coorType=5}, then the conversion
of spherical to cartesian is done in your way. Hopefully ...

Herbert
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