[pstricks] pst-eucl question -- labeling sides of a triangle

[David Arnold]

OK, I have a solution, but don't know if it is the most efficient way  
to tackle this question:

\documentclass{article}
\usepackage{pstricks,pst-eucl}

\begin{document}

\begin{center}
\begin{pspicture}(0,-0.2)(4,3.2)
\pstTriangle[PointSymbol=none,linecolor=blue,PosAngle={0,90,0}](0,0) 
{A}(4,3){B}(4,0){C}
\pstRightAngle[linecolor=blue]{A}{C}{B}
\pstMiddleAB[PointSymbol=none,PointName=none]{A}{C}{b}
\pstMiddleAB[PointSymbol=none,PointName=none]{C}{B}{a}
\pstMiddleAB[PointSymbol=none,PosAngle=135]{A}{B}{c}
\uput[0](a){3 m}
\uput[-90](b){4 m}
\end{pspicture}
\end{center}

\end{document}

David.


On Apr 18, 2009, at 9:25 PM, David Arnold wrote:

All,

OK, This works for letters.

\begin{center}
\begin{pspicture}(0,-0.2)(4,3.2)
\pstTriangle[PointSymbol=none,linecolor=blue,PosAngle={0,90,0}](0,0)
{A}(4,3){B}(4,0){C}
\pstRightAngle[linecolor=blue]{A}{C}{B}
\pstMiddleAB[PointSymbol=none,PosAngle=-90]{A}{C}{b}
\pstMiddleAB[PointSymbol=none,PosAngle=0]{C}{B}{a}
\pstMiddleAB[PointSymbol=none,PosAngle=135]{A}{B}{c}
\end{pspicture}
\end{center}

But what if I want to label sides a and b with  3meters and 4 meters,
respectively.

Still not sure I am using the best approach.

D.

On Apr 18, 2009, at 8:45 PM, David Arnold wrote:

All,

I would like to label the side of the right triangle produced by the
code below with the lower case letter of the upper case letter
marking the vertex directly opposite each side.

What's the best way to do this?

If I were just using nodes, I would:

\ncline{A}{B}
\nbput{$c$}

But I am not sure what to use when I am taking this pst-eucl approach.

What's the most efficient technique?

David


\documentclass{article}
\usepackage{pstricks,pst-eucl}

\begin{document}

\begin{center}
\begin{pspicture}(0,-0.2)(4,3.2)
\pstTriangle[PointSymbol=none,linecolor=blue](0,0){A}(4,3){B}(4,0){C}
\pstRightAngle[linecolor=blue]{A}{C}{B}
\end{pspicture}
\end{center}

\end{document}
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