[pstricks] Points of Intersection

[Herbert Voss]

David Arnold schrieb:

> Suppose that I want a triangle having sides measuring 4, 5, and 6  
> units. Using Geometer's Sketchpad, or Geogebra, I could draw a  
> segment AB of length 6, then add circles of radius 4 and 5 with  
> centers at A and B, respectively. I then could choose on of the  
> points of intersection of the two circles, call it C, and I would  
> have the needed triangle ABC.
> 
> Now, in pstricks I could do some trig, come up with some angles, and  
> use a polar coordinate representation of the point C.
> 
> What I am wondering is this: Is there a slicker way of accomplishing  
> this goal of drawing a triangle with sides 4, 5, and 6 units?

\documentclass[12pt,a4paper]{article}
\usepackage{pst-eucl}

\begin{document}

\psset{unit=1cm}
\begin{pspicture}[showgrid=true](-4,-4)(6,4)
\pstGeonode[PosAngle=-90](0,0){A}
\pstGeonode[PosAngle=-90](6,0){B}
%
\pstCircleOA[linestyle=dashed,linecolor=red,Radius=\pstDistVal{4}]{A}{}
\pstCircleOA[linestyle=dashed,linecolor=blue,Radius=\pstDistVal{5}]{B}{}
%
\pstInterCC[RadiusA=\pstDistVal{4},RadiusB=\pstDistVal{5}]{A}{}{B}{}{E}{F}
\pspolygon(A)(B)(E)
\end{pspicture}

\end{document}

Herbert