[pstricks] new diagram + psmatrix

[Herbert Voss]

s khan wrote:

> Thanks. If we view the pdf file of the following code, we see that some  
> arrows are on the boxes, which looks ugly!
> 
> What I want is: the three-left-arrow heads should be on the ?left sides? 
> of the left boxes and the ?right sides? of the right boxes.
> 
> If possible, I want all the arrows generated from one point of the 
> bottom side of the top box.

-- put the psmatrix first in a box
-- write it with arrows
-- write it again without the arrows to get the boxes
    over the arrows
-- use always \ncdiag

Herbert


\documentclass[a4paper]{article}

\usepackage{pstricks}
\usepackage{pst-node,graphicx}
\definecolor{Pink}{rgb}{1.,0.75,0.8}
\pagestyle{empty}
\setlength\parindent{0pt}
\newsavebox\PBox
\begin{document}
\psset{linearc=0} % it makes a round corner of connection link

\savebox\PBox{%
\begin{psmatrix}[rowsep=1cm,colsep=.5cm]
& \psshadowbox[linearc=5mm,fillstyle=solid,fillcolor=Pink]
    { \begin{tabular}{c}
    $ f1  = a \, q_1 + b \, q_2 $ \\
    $ f2  = c \, q_1 + d \, q_2 $ \\
    \end{tabular} }  &   \\% end of 1st row
\psshadowbox[linearc=5mm,shadow=true,fillstyle=solid,fillcolor=Pink]{
\begin{tabular}{c}
$L_1 = t (q_1+ q_2)\dot{q}_1 - \dot{q}_2 + \frac{dg}{dt}  $ \\
when $a=0, b=1, c=2, d=1$
\end{tabular}
}
& &
\psshadowbox[linearc=5mm,shadow=true,fillstyle=solid,fillcolor=Pink]{
\begin{tabular}{c}
$L_1 = t (q_1+ q_2)\dot{q}_1 - \dot{q}_2 + \frac{dg}{dt}  $ \\
when $a=0, b=1, c=2, d=1$
\end{tabular}
} \\
\psshadowbox[linearc=5mm,shadow=true,fillstyle=solid,fillcolor=Pink]{
\begin{tabular}{c}
$L_1 = t (q_1+ q_2)\dot{q}_1 - \dot{q}_2 + \frac{dg}{dt}  $ \\
when $a=0, b=1, c=2, d=1$
\end{tabular}
}
& &
\psshadowbox[linearc=5mm,shadow=true,fillstyle=solid,fillcolor=Pink]{
\begin{tabular}{c}
$L_1 = t (q_1+ q_2)\dot{q}_1 - \dot{q}_2 + \frac{dg}{dt}  $ \\
when $a=0, b=1, c=2, d=1$
\end{tabular}
} \\
\psshadowbox[linearc=5mm,shadow=true,fillstyle=solid,fillcolor=Pink]{
\begin{tabular}{c}
$L_1 = t (q_1+ q_2)\dot{q}_1 - \dot{q}_2 + \frac{dg}{dt}  $ \\
when $a=0, b=1, c=2, d=1$
\end{tabular}
}
& &
\psshadowbox[linearc=5mm,shadow=true,fillstyle=solid,fillcolor=Pink]{
\begin{tabular}{c}
$L_1 = t (q_1+ q_2)\dot{q}_1 - \dot{q}_2 + \frac{dg}{dt}  $ \\
when $a=0, b=1, c=2, d=1$
\end{tabular}
}
\end{psmatrix}}%
\rput[lt](0,0){\usebox\PBox}%
%\rput[lt](0,0){\resizebox{\linewidth}{!}{\usebox\PBox}}% alternative
\psset{linewidth=1.5pt,arrowsize=7pt,angleA=-90,arm=0}%
\ncdiag{->}{1,2}{4,1}%
\ncdiag[angleB=180]{->}{1,2}{4,3}%
%
\ncdiag{->}{1,2}{3,1}%
\ncdiag[angleB=180]{->}{1,2}{3,3}%
%
\ncdiag{->}{1,2}{2,1}%
\ncdiag[angleB=180]{->}{1,2}{2,3}%
\rput[lt](0,0){\usebox\PBox}%
%\rput[lt](0,0){\resizebox{\linewidth}{!}{\usebox\PBox}}% alternative

\end{document}