[pstricks] Displaying a unsymetrich diagram

Nicolai Emig Nicolai at areaemig.de
Mon Nov 21 19:00:50 CET 2005


Herbert Voss wrote:

> Nicolai Emig wrote:
>
>> \psset{yunit=100cm}
>> \begin{pspicture}(-0.5,-1.1)(11,-1.6)%
>>   \psaxes[dy=1cm,Dy=0.01,Oy=-1.10]{->}(0,-1.10)(11,-1.6)
>
>
> how should this work? You have a half PSTricks unit:
> -1.6 - (-1.10) = -0.5


What do you want to tell me with that?

Where can I find a docu about that pstricks topic?

>
> and with a scaling of 100cm you get a y-axis of 50cm!
>
> \psset{yunit=10cm}
> \begin{pspicture}(-0.5,-1.1)(11,-1.6)%
>   \psaxes[dy=1cm,Dy=0.1,Oy=-1.1]{->}(0,-1.10)(11,-1.6)
>   \psdots(1,-1.577)(2,-1.526)(3,-1.475)(4,-1.423)(5,-1.373)
>   \psdots(6,-1.321)(7,-1.270)(8,-1.217)(9,-1.170)(10,-1.118)
> \end{pspicture}
>
>
> Herbert
>
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