[OS X TeX] Binomial Expansion

Alain Schremmer Schremmer.Alain at gmail.com
Thu Nov 23 22:40:35 CET 2006


Claus Gerhardt wrote:

> My final recommendations are
>
> \newcommand{\expand}[1]{\polyprint{#1}}
>
> \newcommand{\expa}[1]{#1=\polyprint{#1}}
>
> Possible variant of the last one
>
> \newcommand{\expb}[1]{&#1=\\&\polyprint{#1}}
>
> using e.g. amsmath and
>
> \begin{equation}
> \begin{aligned}
> \expb{(x+1)(x^3+6)^3+9}
> \end{aligned}
> \end{equation}

1) I am truly overwhelmed as this is no small present. I am most 
grateful since \Expand will save me a lot of time when I rewrite the 
last part of the magnum opus because I use (Laurent) polynomial 
expansions (asymptotic expansions if you would) to investigate functions.

    For example, given, say, f(x) = \frac{x^3 - 1}{x - 2},

        - dividing in descending powers of x gives the behaviour near
        infinity: x^2 + (…)

        - letting x = 2+h and then dividing in ascending powers of h
        gives the behaviour near 2: 7h^-1 + (…)

    where (…) stands for the appropriate o[h^n] (the students for whom
    this is don't need more at this point of their education).

So, now you can see better why I need both (x+2)^3 —which I now have 
thanks to you—and division in ascending powers.

2) I see that polyprint is the crucial command and I was indeed trying 
to isolate the crucial command … by commenting out code. I got rid of 
the Horner stuff but, as your first email arrived, I was getting nowhere 
fast. So, here too thanks for preventing me to waste more time than I 
can afford to waste.

3) I went through each one of your commands and I thought that you might 
be interested in the result:

    \expand{(x+2)}{(x+3)} expands beautifully
    \expand{(x+a)}{(x+b)} gives "(1a+1b)" as middle term.
    \expand{(x+h)^{3}}{1} expands beautifully
    \expand{(x_{0}+h)^{3}}{1} gives an error that I assume is due to
    polyprint not liking _{0}

    \Expand{(x+a)(x+b)} gives "(1a+1b)" as middle term.
    \Expand{(x+2)^{3}} expands beautifully
    \Expand{(2+h)^{3}} expands but parentheses surround the ascending
    expansion!
    \Expand{(x+h)^{3}} expands beautifully
    \Expand{(x_{0}+h)^{3}} gives the same error that I assume is due to
    polyprint not liking _{0}

I couldn't get expa[2] to work

and, with expa[1]

    \expa{(x+2)(x+3)} expands beautifully
    \expa{(x+2)^{3}} error "!Missing $ inserted"
    \expa{(2+h)^{3}} error "!Missing $ inserted"

With expb

    \begin{equation}
    \begin{aligned}
    \expb{(x+2)(x+3)}
    \end{aligned}
    \end{equation writes the expansion under (x+2)(x+3) rather than after =.

    \begin{align*}
    \expb{(x+h)^{3}}
    \end{align*} writes the expansion under (x+h)^{3} rather than after =

    \begin{align*}
    \expb{(x+2)^{3}}
    \end{align*} ditto

    \begin{align*}
    \expb{(2+h)^{3}}
    \end{align*} ditto and here too parentheses surround the ascending
    expansion


Well, that's it. Of course I couldn't fix anything but, other than the 
issue of the parentheses surrounding expansions in ascending powers, 
\Expand does exactly what I wanted (But expb is nice too). So, that's 
what I will be using and as for the surronding parentheses I will just 
put a footnote in the text saying that they are an artifact and that, 
under the GPL, anyone is free to fix it.

Well, I wish I understood how you did it but, hopefully, that will come 
later. In the meantime, thanks very much again.

Best regards
--schremmer



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