[l2h] feature or bug?
Ralf Scholl
rasch@skillsonline.de
Wed, 5 Sep 2001 12:04:46 +0200
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Is this an undocumented feature?
When I'm trying to convert:
$\mathbf{U\Lambda U^\mathrm{T}}$
l2h complains with: ? brace missing for \^or _
and renders the T not in the exponent but on the baseline.
(LaTeX has no problem with this expression.)
l2h renders the expression correct, when I enclose the \mathrm{T} in =
braces, but it took me nearly two hours to find this!
Ralf Scholl
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<DIV><FONT face=3DArial size=3D2>Is this an undocumented =
feature?</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>When I'm trying to =
convert:</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>$\mathbf{U\Lambda =
U^\mathrm{T}}$</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>l2h complains with: ? brace =
missing=20
for \^or _</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>and renders the T not in the exponent =
but on the=20
baseline.</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>(LaTeX has no problem with this=20
expression.)</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>l2h renders the expression correct, =
when I enclose=20
the \mathrm{T} in braces, but it took me nearly two hours to find=20
this!</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>Ralf Scholl</FONT></DIV></BODY></HTML>
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