<div dir="ltr">Now I see what you're producing. You could use the following:<div><br></div><div><div> \rput(5,5){\psline{->}(0,0)(4.7cm;-125)}</div><div> \rput(10.5,5){\psline{->}(0,0)(4.0cm;-60)}</div></div>
<div><br></div><div>This translates the starting point of the lines to the origin of the circle, and then uses the circle radius (plus a specified angle) to draw the line.</div></div><div class="gmail_extra"><br><br><div class="gmail_quote">
On Wed, Feb 12, 2014 at 11:01 AM, Rich Shepard <span dir="ltr"><<a href="mailto:rshepard@appl-ecosys.com" target="_blank">rshepard@appl-ecosys.com</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
On Wed, 12 Feb 2014, Werner Grundlingh wrote:<br>
<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
How about drawing the line over (and into) the circle, but setting the<br>
circle *after* the line with a (white) filled center?<br>
</blockquote>
<br>
Werner,<br>
<br>
I'll have to think about this. In the code I posted the radius of each<br>
circle has meaning so if your suggestion produces a radius it will work for<div class="HOEnZb"><div class="h5"><br>
me.<br>
<br>
Thanks,<br>
<br>
Rich<br>
<br>
-- <br>
Richard B. Shepard, Ph.D. | Have knowledge, will travel.<br>
Applied Ecosystem Services, Inc. |<br>
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