<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta content="text/html;charset=ISO-8859-1" http-equiv="Content-Type">
</head>
<body bgcolor="#ffffff" text="#000000">
Dear Zbigniev,
<blockquote cite="mid:70EC2D9B-730A-4D5E-8A8E-44CFC2589860@tufts.edu"
type="cite">
<div>
<div><span class="Apple-style-span"
style="border-collapse: separate; color: rgb(0, 0, 0); font-family: Helvetica; font-size: 12px; font-style: normal; font-variant: normal; font-weight: normal; letter-spacing: normal; line-height: normal; orphans: 2; text-indent: 0px; text-transform: none; white-space: normal; widows: 2; word-spacing: 0px;">
<p style="margin: 0px;"><font
style="font-family: Helvetica; font-style: normal; font-variant: normal; font-weight: normal; font-size: 12px; line-height: normal; font-size-adjust: none; font-stretch: normal;"
face="Helvetica" size="3"><br>
</font></p>
<p style="margin: 0px;"><font
style="font-family: Helvetica; font-style: normal; font-variant: normal; font-weight: normal; font-size: 12px; line-height: normal; font-size-adjust: none; font-stretch: normal;"
face="Helvetica" size="3">How do I get the curve given parametrically
by</font></p>
<div>x=t</div>
<div>y=1</div>
<div>z=0.5-1.5*t^2</div>
<div>?</div>
</span></div>
</div>
</blockquote>
Try out the following. Varying the _r_ parameter blows the line into a
tubelike line.<br>
You do everything right as far as i can see. I cancelled out some
unnecessary packages for your example.<br>
<pre class="moz-signature" cols="65">\documentclass[11pt]{article}
\usepackage{pst-solides3d}
\begin{document}
\begin{pspicture}(-0.5,-2)(3,3)
\defFunction[algebraic]{curvey}(t){t}{1}{0.5-1.5*t^2}
\psSolid[%
object=courbe,
r=0.01,
range=-1.0 1.0,
resolution=720,
linecolor=blue,
linewidth=1pt,
function=curvey,
action=draw**
]%
\end{pspicture}
\end{document}
</pre>
<br>
<br>
Hope this will help.<br>
<br>
Regards,<br>
<br>
Juergen<br>
<pre class="moz-signature" cols="65">
</pre>
</body>
</html>