# [OS X TeX] OT: peculiar table formatting

Peter Dyballa Peter_Dyballa at Web.DE
Wed May 3 23:47:59 CEST 2006

Am 03.05.2006 um 17:15 schrieb Bruno Voisin:

> I was wondering whether anyone here would know about more elegant
> solutions to the same problems.

Well, I'd call this a simple approach (which is good enough for me):

\begin{tabular}{cllllll}%cccccc}%
& \multicolumn{2}{c}{$\fno \gg 1$} & \multicolumn{4}{c}{$\fno \ll 1$} \\
& \multicolumn{2}{c}{\rule[1mm]{25mm}{0.5mm}}
& \multicolumn{4}{c}{\rule[0.5mm]{80mm}{0.5mm}} \\
Region & \multicolumn{1}{c}{Inner} & \multicolumn{1}{c}{Outer} &
\multicolumn{1}{c}{Middle} & \multicolumn{1}{c}{Top \& Bottom} &
\multicolumn{1}{c}{Shear} & \multicolumn{1}{c}{Upper \& Lower} \\
Vertical distance     & $O(1)$ & $O(\fno)$     & $O(1)$
& \rule{6.25mm}{0mm}$O(\fno)$      & $O(\fno)$   & \rule{7.5mm}
{0mm}$O(1)$ \\
Horizontal distance   & $O(1)$ & $O(\fno)$     & $O(1)$
& \rule{6.25mm}{0mm}$O(\fno^{1/2})$ & $O(1)$      &\rule{7.5mm}
{0mm}$O(1)$ \\
Perturbation velocity & $O(1)$ & $O(1/\fno^2)$ & $O(1)$
& \rule{6.25mm}{0mm}$O(1)$         & $O(\fno)$   & \rule{7.5mm}
{0mm}$O(\fno)$ \\
Vertical displacement & $O(1)$ & $O(1/\fno)$   & $O(\fno^2)$
& \rule{6.25mm}{0mm}$O(\fno)$      & $O(\fno^2)$ & \rule{7.5mm}
{0mm}$O(\fno^2)$
\end{tabular}

The rulers are too thick, their lifts are different -- just to assure
that there are means for some optimisation ... also in right-shifting
some elements.

--
Greetings

Pete

"What is this talk of 'release'?  Klingons do not make software
'releases'.  Our software 'escapes' leaving a bloody trail of
designers and quality assurance people in its wake."

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